not really
but the length is always the longer side :)
No. Because of the commutative law of multiplication, it makes no difference.
Select any number, W, between 0 and 4 units.Consider a rectangle with width W and length, L = 8 - W units.Then the rectangle with dimensions L and W will have a perimeter of 16 units.Since there are infinitely many possible values for W, there are infinitely many possible answers to the question.
Select any two whole numbers that sum to half of 26 = 13.
Select any one side and divide its length into 5 equal parts. Draw lines that are parallel to the adjacent side to the opposite side. This will divide the rectangle into 5 equal strips.
Select any number, B, less than or equal to 3 units. Let L = 6 - B units. Then, a rectangle with length L and breadth B will have a perimeter of 12 units.
You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.
You can select the cable length in the option box.
If you don't know the width, area or length, you would have to have several other measurements that would permit you to calculate the width or length. A rectangle's main formula is l x w x h (length times width x height). If you don't have two of them, finding the third one is complicated, but doable under some select circumstances. If you had the lengths of two sides of a triangle with two vertices matching two of the rectangle's vertices, you could use trigonometry find the length of the shared side. If this shared side was the length then you would be golden. Or you could measure.
To add a rectangle in Premiere Pro, you can use the "Rectangle Tool" in the "Graphics" workspace. Simply select the tool, draw a rectangle on the screen, and customize its size, color, and position as needed.
Yes, but it doesn't matter what two you select to start one.
Yes, but it doesn't matter what two factors you select to start one.
It doesn't matter what you select to start, but all the factors must be prime at the completion.