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No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.

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Q: Does sound Intensity decrease linearly with distance?
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Related questions

How is the intensity of a sound related to the distance between the source and the receiver?

The intensity of a sound will decrease according to an inverse square law.


How does the intensity of a sound wave change if the distance from the source is reduced by a factor of 4?

- 6 dB is incorrect. It will decrease by 12 dB.


Why does the intensity of a sound decrease as the distance from the source increases?

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How will decreasing the amplitude of the sound waves from a TV affect its intensity?

Amplitude is intensity. It refers to the strength of a sound wave, which the human ear interprets as volume or loudness and if you decrease the amplitude you also decrease its intensity.


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You mean by the word 'volume' the intensity of sound wave. Intensity is directly proportional to the square of the amplitude.


The intensity of a sound describes?

Its loudness at a particular distance


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Sound intensity or acoustic intensity is defined as the sound power Pacper unit area A. The usual context is the noise measurement of sound intensity in the air at a listener's location as a sound energy quantity.


How does the intensity of a sound wave change if the distance from the source increases by a factor of 2?

The intensity increases by a factor of 4-APEX


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By what factor will the sound of a source change the intensity of the waves if the distance is tripled from the sound source?

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The sound of a bullfrog attracts a mate How much quieter is the sound if the mate is 4 times further away if the sound follows the inverse square law?

Well, it has to follow the inverse square law, so that as distance increases, the sound intensity drops by the square of the proportionate change in distance. The intensity will be 1/16 at 4 times the distance.