No, divisors are integers and square root are often not. So the square root of 4, for example, is 2 and yes 2 is a divisor of 4. But the square root of 5 is not a divisor of 5 because it is not an integer. So sometimes square root are divisors and more often they are not.
if the dividend is a perfect square and the divisor is its square root
no but it means the same as your foot
sqrt(324) = ±1818the square root is 18
The standard deviation of a normal deviation is the square root of the mean, also the square root of the variance.
Shorthand for "square root" and can also refer to cube root ("third root") etc etc.
If you mean, the square root of 4 multiplied by the square root of 5, that is 2x5=10 If you mean, the square root of ( 4x25), that is the square root of 100 which is 10
The principal square root is the non-negative square root.
The square root is the number which, multiplied by itself, gives the number you are square rooting.For example,The square root of 36 is 6, because 6 * 6 = 36.* * * * *Note, though, that (-6)*(-6) is also + 36 so -6 is also a square root of 36
No. Standard deviation is the square root of the mean of the squared deviations from the mean. Also, if the mean of the data is determined by the same process as the deviation from the mean, then you loose one degree of freedom, and the divisor in the calculation should be N-1, instead of just N.
An algorithm is process or set of rules for doing something If we are looking for square rots which are integers then an algorithm might look like this Put the number whose root is sought into a variable - the dividend. Put 2 into a variable - the divisor Begin a loop divide the dividend by the divisor put the result into a variable - the quotient if the quotient = the divisor then the quotient is the square root of the divident else, add 1 to the divisor next loop
Yes, if your equation is f(x) = sqrt5(x). The square root is also a function itself, if that's what you mean.
You mean square root of 25? (Answer: 5)