Volume
They are exactly the same amount
fill a glass (or any container large enough) with water, then drop the object gently in the glass. However much water is displaced (overflown out of the glass), that is the volume of the object in its place.say the amount of water displaced weighed 10g10g = 1cl1cl = 10cm^3Therefore the object displaced 10cm^3 of water, making that its total volume.
the weight of the displaced water is equal to the weight of the object
I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.
By placing the object in water and the volume of water displaced is equal to the volume of the object immersed
the object's volume
They are exactly the same amount
The volume of the submerged object.
volume
VOLUME :)
Measure the amount of liquid that is displaced by the object in question (you will probably need a graduated cylinder). The amount of liquid displaced is the volume of the object. Then, since you have the volume of the object, you can find the mass of the object. Mass=Density x Volume.
Use a measured water cylinder, drop in the object, the amount of water displaced represents the volume of the object
That is the amount of fluid displaced by the object beneath the surface of the fluid.
No. It depends on the amount of space the object occupies, which is known as its "volume".Within that volume, it may have a large mass, a small mass, or an in-between mass, depending onwhat substance comprises the object. In each case, it would displace the same amount of liquid.In fact, where the question uses the slippery word "amount", it's really talking about "volume" of liquid.
fill a glass (or any container large enough) with water, then drop the object gently in the glass. However much water is displaced (overflown out of the glass), that is the volume of the object in its place.say the amount of water displaced weighed 10g10g = 1cl1cl = 10cm^3Therefore the object displaced 10cm^3 of water, making that its total volume.
Displacement. You have a beaker with a known amount of water. Put the object in. Subtract the current volume minus the starting volume (of water). The difference is the amount of water displaced, telling you the volume of the object.
the weight of the displaced water is equal to the weight of the object