Let's draw the parallelogram ABCD in which both pairs of opposite sides are parallel and congruent.
From the vertices A and C draw the altitudes AE and CF respectively to the sides DC and AB of the parallelogram, which separates it into two congruent right triangles AED and CFB, and the rectangular AFCE. So that the area of the parallelogram equals to
2(AAED) + AAFCE
= 2[(DE x AE)/2] + (EC x AE)
= (DE x AE) + (EC x AE)
= (DE + EC)AE
= DC x AE
= base x height
Thus, the area of any parallelogram equals to the product of its base and height.
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
For a cuboid it gives its volume.
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
Area equals LxW (Length times width)
length times width length times width
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
Base times height tims width equal to length
For a cuboid it gives its volume.
Area is l (length) x w (width), Volume is measured with l (length) x w (width) x h (height).
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
Area equals LxW (Length times width)
volume The 'Volume' of an object or space
15 feet.
63 feet
the length is equal to 160,083
Indeed there is a relationship. Density is equal to the mass divided by the volume (height times width times length). So, height is equal to mass divided by (height times length times width) or H= M/(HLW)
The perimeter of a rectangle is equal to 2*length + 2* width. In this case, we will say 2x + 2y = p = 48. Since the length is equal to 3 times the width, the equation now becomes p = 6*y + 2*y, or just p = 8y. Now since p =48, y must equal 6. And since the length is three times the width (y), the length is 18.