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Sure. That's true of a median in every isosceles triangle, and every median in an equilateral triangle. In fact it is true for any median of any triangle. The two parts may not be the same shapes but they will have the same area. That is why the point where the three medians meet (centroid) is the centre of mass of a triangular lamina of uniform thickness.
Centre of area for plane triangle (no thickness, theory only) Line from apex to middle of opposite side, repeat for another apex, intersection is centre of area. > If triangle has thickness go from centre of area vertically down to half thickness of material. This is the centre of mass or centroid
There are three main methods: Method 1: The simplest situation is one in which the irregular shape can be divided up into shapes whose areas can be calculated. For example, the outline of an ice-cream cone may be viewed as a triangle with a semi-circle on top. So calculate the areas for the bits and add them up. Method 2: Trace the shape onto dense lamina of uniform thickness. Cut out the shape and measure its mass. Next cut out a UNIT square of the same lamina and measure its mass. Then Area of irregular shape = Mass of irregular lamina/Mass of lamina square. Method 3: Trace the shape onto a sheet of paper with square gridlines on it. Count the number of whole (or almost whole) squares inside the shape = A. Count the number of squares where approximately half is inside the area = B. Ignore all squares where only a tiny bit is in the marked area. Then, Area of irregular shape = (A+B/2)*area of unit square in the grid. The finer the grid, the more accurate your result, but also the harder you'll have to work.
"Acre" is an area. One acre of area always covers 43,560 square feet, no matter what its shape might be. If an acre of ground is enclosed within a circular boundary, then the area of half of the circle is 1/2 acre.
If you can find the perimeter, then you can find the area. Calculate the perimeter. Then times the top sides by the left and right sides (and obviously the bottom!) the there you have it. The area of an irregular shape! * * * * * Total nonsense! The above applies only to a square or rectangle - and a square in not even an irregular shape! There are three main methods: Method 1: The simplest situation is one in which the irregular shape can be divided up into shapes whose areas can be calculated. For example, the outline of an ice-cream cone may be viewed as a triangle with a semi-circle on top. So calculate the areas for the bits and add them up. Method 2: Trace the shape onto dense lamina of uniform thickness. Cut out the shape and measure its mass. Next cut out a UNIT square of the same lamina and measure its mass. Then Area of irregular shape = Mass of irregular lamina/Mass of lamina square. Method 3: Trace the shape onto a sheet of paper with square gridlines on it. Count the number of whole (or almost whole) squares inside the shape = A. Count the number of squares where approximately half is inside the area = B. Ignore all squares where only a tiny bit is in the marked area. Then, Area of irregular shape = (A+B/2)*area of unit square in the grid. The finer the grid, the more accurate your result, but also the harder you'll have to work.
A circle will always have its centroid withing its area.
Sure. That's true of a median in every isosceles triangle, and every median in an equilateral triangle. In fact it is true for any median of any triangle. The two parts may not be the same shapes but they will have the same area. That is why the point where the three medians meet (centroid) is the centre of mass of a triangular lamina of uniform thickness.
The curved area between the spinous process and the transverse process.
it lies in the oral mucosa of mouth
The centroid of a parabola is found with the equation y = h/b^2 * x^2, where the line y = h. Additionally, the area is 4bh/3.
The surface area between the tip and the bottom of a leaf is called the lamina. The lamina is attached to the plant stem by the petiole. The lamina is supported by veins, which carry nutrients to the leaf tissue.
Should the triangle have thickness, then from the centre of area (centroid) go into the material (normal to the surface) to half its thickness, this point is the centre of gravity.
Centre of area for plane triangle (no thickness, theory only) Line from apex to middle of opposite side, repeat for another apex, intersection is centre of area. > If triangle has thickness go from centre of area vertically down to half thickness of material. This is the centre of mass or centroid
The lamina is the expanded portion or blade of a leaf and it is an above-ground organ specialized for photosynthesis. For this purpose, a leaf is typically, to a greater or lesser degree, flat and thin, to expose the chloroplast containing cells (chlorenchyma) to light over a broad area, and to allow light to penetrate fully into the tissues.
Square feet is a measure of area in the obsolete Imperial measurement system. There are simple formulae for shapes such as circles, ellipses, triangles, parallelograms (including special cases), trapezia and regular polygons with 5 or mire sides. The simplicity of the formula depends on what information you have about the shape. Then there are less simple formulae for more complex shapes.For totally irregular shapes the options are the grid method and the lamina method. The first involves copying the shape onto a grid and then estimating the area by counting the number of cells of the grid inside the outline. The lamina method requires making a replica of the shape onto a lamina of uniform density and then deriving its area by comparing the mass of the lamina with that of a 1 foot square (or related size) of the lamina.
Centroid: Centroid is the point, where the whole area of plane is going to be act. It is valid only for plane figures, like the center of a circle or a square plate. ( applicable for 2 dimensional problem) Center of Gravity Center gravity is the point, where whole weight of the body is going to be act. It is irrespective of the orientation of the body. (applicable for 3 dimensional problem)
The lamina is green due to the chlorophyll inside. It is flat to maximise the surface area so that it can absorb as much sunlight as possible, while its thin nature is to facilitate gaseous exchange(and make it easier to absorb sunlight).