yes it is a continuous function.
The differential of the sine function is the cosine function while the differential of the cosine function is the negative of the sine function.
Inverse of Cosine is 'ArcCos' or Cos^(-1) The reciprocal of Cosine is !/ Cosine = Secant.
I was not aware that the cosine function was in fashion!The range, on the other hand, is [-1, 1].
The argument of the cosine function must be (2pi/3)*x radians
Tangent = sine/cosine provided that cosine is non-zero. When cosine is 0, then tangent is undefined.
Yes. The cosine function is continuous. The sine function is also continuous. The tangent function, however, is not continuous.
Yes, it does "appear" to be continuous, by the simple fact that it is continuous for all values of the input.
The differential of the sine function is the cosine function while the differential of the cosine function is the negative of the sine function.
Cosine is a trigonometrical function.
-1<cosine<1
The Y-Intercept of the cosine function is X = 0, Y = cosine(0) = 1.
Inverse of Cosine is 'ArcCos' or Cos^(-1) The reciprocal of Cosine is !/ Cosine = Secant.
False; the cosine function is an even function as cos(-x) = -cos(x).
I was not aware that the cosine function was in fashion!The range, on the other hand, is [-1, 1].
The argument of the cosine function must be (2pi/3)*x radians
Tangent = sine/cosine provided that cosine is non-zero. When cosine is 0, then tangent is undefined.
An even function is one where f(x) = f(-x) For cosine, cos(x) = cos(-x), thus cosine is an even function.