no, the square root of 49 is 7 (since 7 times 7 is 49)
the square root of 49 equals 7
49
the 4th root of 49 is the square root of the square root of 49 since square root 49 =7 then simplify is square root of 7
It's not. Take 49 and 16 for example. The square root of the sum is the square root of 65. The sum of the square roots is 11.
if x^2 = 49, then the square root property says you can take the square root of both sides as long as you make one a plus-minus. x^2 = 49, which means square root of x^2 = plus minus the square root of 49 the square root of 49 is 7, so +- 7. We get: x = plus/minus 7 (this means either positive 7 or negative 7)
square root of 49 is 7 square root of 121 is 11
49 is the square root of 7
147 49,3 7,7,3 The square root of 147 equals the square root of 49 times the square root of 3 which is 7 times the square root of 3.
The square root of 49 is 7.7 times 7 is 49, so the square root of 49 is 7. 7
No. The square root of 49 is 7.
The square root of 4 is 2, if you multiply that by the square root of 49, which is 7, you get 14.
The square root of 121 is 11 and 11 plus 49 = 60