Wiki User
∙ 2015-09-24 09:58:12Yes, the sum of any three consecutive counting numbers has a factor of 3.
Wiki User
∙ 2015-09-24 09:58:1224 + 25 + 26 = 75
Any three consecutive integers.
I think I know what you're asking, but it doesn't work like that. The sum of any set of numbers is a single number and single numbers don't have common factors until they are compared to at least one other number. The sum of three consecutive counting numbers will be at least a multiple of 3.
Any three-digit multiple of 60, from 120 to 960, has the first five counting numbers as factors.
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
There are no three consecutive numbers with a sum of 170.
The answer to that question is 49,50,51
There are no sets of three consecutive numbers totaling 118.
19, 20, 21
There are no three consecutive numbers that are squares. Otherwise, there are an infinite sets of squares of three consecutive numbers: for example, {1,4,9}, or {4,9,16} or {576, 625, 676}
This is no set of three consecutive numbers that when multiplied equal 387.
The three consecutive odd prime numbers are 3, 5, and 7.