It depends on the cube's size, not the cube's weight, due to the amount of displacement caused by a larger sized cube than when compared to a smaller sized cube.
When a solid body is totally immersed in a fluid, the upthrust is equal to the weight of fluid displaced. This weight is the volume of the solid body times the density of the fluid. Fluids of different densities will produce different upthrusts.Note. If the body is floating on the surface of the fluid, the upthrust does not depend on the density of the fluid. The floating solid will sink into the fluid until the upthrust exactly equals its weight, then it won't sink any deeper. In flotation the buoyancy force always equals the weight of the body, whatever the fluid's density.
Apparent weight of an object is the weight of an object when the object is partially or totally immersed in a fluid{liquid/gas} normally apparent weight of an object is less than the real weight of an object due to an upward force {upthrust} which is produced by the pressure difference inside the fluids.
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upthrust=buoyant force=weight of the body immersed in d liquid so gravity and mass is a cause of upthrust as weight of a body=mass* gravity
When an object is immersed in liquid then an equal volume of liquid would be displaced to the upper surface. The weight of this expelled liquid would be used as a force to push up the immersed object. Hence it is named as upthrust or buoyant force
The following procedure can be used to determine the upthrust of a body using Archemede's principle. i) Determine the weight of the body using spring balance and record it as W1. ii) Pour water into eureka can up to its spout. iii ) Take empty bearker, weigh it, record its weight as W2 and place it under the spout of the eureka cane. iv ) Record the weight of the body when is totally immersed in water as W3 v ) Remove the beaker and reweigh it togehter with its contents (overflowed water after immersing the stone) record the weight as W4 There fore uor upthrust of the body is given as, upthrust= loss of weight in water = W1-W2 Weight of displaced water= W4-W2 Hence upthrust =loss of weigt in water =weigth of water displaced The following procedure can be used to determine the upthrust of a body using Archemede's principle. i) Determine the weight of the body using spring balance and record it as W1. ii) Pour water into eureka can up to its spout. iii ) Take empty bearker, weigh it, record its weight as W2 and place it under the spout of the eureka cane. iv ) Record the weight of the body when is totally immersed in water as W3 v ) Remove the beaker and reweigh it togehter with its contents (overflowed water after immersing the stone) record the weight as W4 There fore uor upthrust of the body is given as, upthrust= loss of weight in water = W1-W2 Weight of displaced water= W4-W2 Hence upthrust =loss of weigt in water =weigth of water displaced The following procedure can be used to determine the upthrust of a body using Archemede's principle. i) Determine the weight of the body using spring balance and record it as W1. ii) Pour water into eureka can up to its spout. iii ) Take empty bearker, weigh it, record its weight as W2 and place it under the spout of the eureka cane. iv ) Record the weight of the body when is totally immersed in water as W3 v ) Remove the beaker and reweigh it togehter with its contents (overflowed water after immersing the stone) record the weight as W4 There fore uor upthrust of the body is given as, upthrust= loss of weight in water = W1-W2 Weight of displaced water= W4-W2 Hence upthrust =loss of weigt in water =weigth of water displaced The following procedure can be used to determine the upthrust of a body using Archemede's principle. i) Determine the weight of the body using spring balance and record it as W1. ii) Pour water into eureka can up to its spout. iii ) Take empty bearker, weigh it, record its weight as W2 and place it under the spout of the eureka cane. iv ) Record the weight of the body when is totally immersed in water as W3 v ) Remove the beaker and reweigh it togehter with its contents (overflowed water after immersing the stone) record the weight as W4 There fore uor upthrust of the body is given as, upthrust= loss of weight in water = W1-W2 Weight of displaced water= W4-W2 Hence upthrust =loss of weigt in water =weigth of water displaced
The upthrust on a body wholly or partly immersed in a fluid is equal to the weight of the fluid displaced.One of the earliest laws of physics to be correctly stated, this is known as Archimedes' principle.
Archimedes was a Physics Fluids Scientist. Dates: 287-212 BC. The description of his scientific law is the Principle of Displacement, when a body is totally or partially immersed in a fluid it experiences an upthrust equal to the weight of the fluid displaced. Principle of Flotation, when a body floats it displaces a weight of fluid equal its own weight.
Upthrust cancels weight out, weight is there but you do not feel it.
Upthurst acts on a body which is partially or totally immersed in a fluid and it is equal to the weight of fluid displaced.
Certain things float in water because their density is less than the density of water. If something experiences more upthrust in water than its weight(upthrust>weight) or upthrust=weight, then it floats in water.
Same as his weight