Q: Does y vary directly as x in y equals 8x?

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x2-8x=0 ( add 8x to both sides) x2 =8x (divide by x) x=8 ( x2divided by x equals x)

0

x*x - 8x +16 = 0 x*x = 8x + 16 x - 16 = _/8x x_/-4 = 2 x = 2

3 - x = 8x = 3 - 8x = - 5

8x=7x-7 x=-7

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x2-8x=0 ( add 8x to both sides) x2 =8x (divide by x) x=8 ( x2divided by x equals x)

0

5x-3=2-8x 5x-3+3=2-8x+3 5x=5-8x 5x+8x=5-8x+8x 13x=5 x=5/13

8x + 3 = 35 8x = 32 x = 4

2-8x=22 -8x=20 -x=2.5 x=-(2.5)

No.

X=5

8x + 8=40 8x=40-8 8x=32 x=32/8 x=4

x*x - 8x +16 = 0 x*x = 8x + 16 x - 16 = _/8x x_/-4 = 2 x = 2

8x = -104 Therefore, x = -104/8 x = -13

3 - x = 8x = 3 - 8x = - 5

8x=7x-7 x=-7