x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)
I am trying to read this right: (9 x 5) - x3 = ? or 9 x (5 - x3) = ? Which one is it?
p x = 20 x5 - 20 x4 + 24 x2 q x = 4 x2 p = 20 x4 - 20 x3 + 24 x, if xis not equal to 0 p / qx = ( 20 x4 - 20 x3 + 24 x) / (4 x2) = (5 x4 - 5 x3 + 6 x) / x2 So p / qx = 5 x2 - 5 x + 6/x if x is not equal to 0
10x + 5 unless you know what x & y are * * * * * Perhaps this answer will be of help: x3 + x2 + 5x + 5 = (x + 1)(x2 + 5). If you are willing to go to complex roots, then, x3 + x2 + 5x + 5 = (x + 1)(x2 + 5). = (x + 1)(x + i√5)(x - i√5); in which case, x = -1 or ±i√5.
x3 + 12x2 - 5x = x(x2 + 12x - 5) = x(x + 6 - √41)(x + 6 + √41)
It is x = -5
x + 3 = 6xx - x + 3 = 6x - x3 = 5x3/5 = 5x/53/5 = x
x3 - 3x2 - 9x - 5 = 0 (x + 1)(x2 - 4x - 5) = 0 (x + 1)(x - 5)(x + 1) = 0 x ∈ {-1, 1, 5}
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
x3+x2+x First, factor out the x: x(x2+x+1) Could stop there, but the rest is factor-able using imaginary numbers: x(x+.5(1+i(3).5)(x+.5(1-i(3).5), where i = (-1).5, or sqrt(-1)
It is an equation of: 5x+3 = 28 and its solution is x = 5 5 times x plus 3 equals 28. Subtract 3 from both sides of the equation. 5 times x equals 25. Divide both sides of the equation by 5. x equals 5. (stop)
x=4.
X3 - 4 = 2 X3 = 6 X = 61/3 X = about 1.817
what x3 equals 63 is:21x3=63
x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)
x-17 = 16-5 x = 16-5+17 x = 28
X3-5=3 X3=3+5 X3=8 cube root of X3=cube root of 8 X=1.68 I hope this could help. There's not really any good ways to write algebra in a normal text box.