It is a fraction of the form (6*k)/(8*k) where k is any non-zero integer or a common factor of 6 and 8.
It is a fraction of the form (6*k)/(8*k) where k is any non-zero integer or a common factor of 6 and 8.
24*k where k is any integer.
Any number of the form 84*k, where k is an integer, is evenly divisible.
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
Rewrite and see the question. 8 - k + 3 = ?. k= 6. Fill in the "k". Now the problem is 8 - 6 + 3 = ? PEMDAS would be helpful. For me, I put it PE(MD)(AS) to see that the multiplication and division is left and right and same for the addition and the subtraction. Since there is no P, E, M, or D, I would cross that out. So now it is left to right. 8 - 6 = 2 2 + 3 = 5 The answer is 5.
9.333 x 6 = 56
-12k - 96
My Fair Wedding - 2008 Inspired by Kim K 6-8 was released on: USA: 27 October 2012
8k-7-3k=1? 5k-7=1 5k=8 k=8/5 8k-7 =-3k+1 11k-7=1 11k=8 k=8/11 8k-7-3k+1=0 5k-6=0 5k=6 k=6/5=1.2 depends on where = sign is in the question
red Q, red Q, black Q, black Q, J, 6, 7, 3, K, 2, 5, 2, 5, J, 7, K, 6, 7, 3, K, 6, 7, 3, K, 2, 5, 10, 10, 10, 10, J, 4, 4, 8, 8, 8, 4, 9, 9, 9, 9, 8, A, A, A, A, "What The Hell", J, 2, 3, 4, 5, 6 (2-6 need to be spades)
They are members of the infinite set of numbers of the form 24*k where k is an integer.