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The question is rather simple, since you need an even number greater than 700 that is three digits we have a number that is of the form

7-even-even (odd + odd + even = even but 11 is of the form 2k+1 which is odd)
8-odd-even (odd +even+even = an even number)
902, 920 or 911 (this is because the sum of the digits is 11 and using 9 we would have 9 +X + Y = 11 which means that X + Y = 2 and we have a linear diophantene equation with the solutions (1,1), (2,0) (0,2)

for example 704 (7 + X + Y = 11 means X + Y = 4 so we have (2,2), (4,0) (0,4) ,(1,3) and (3,1)

Also,

803 because 8 + X + Y = 11 or X + Y = 3 and you would get (0,3) (1,2) (2,1) (3,0) as solutions.

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Q: Even 3-digit number greater than 700 whose digits total 11?
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