0
#include <iostream>
int main()
{
int num;
std::cout << "Enter a number: ";
std::cin >> num;
if(num % 2 == 0)
{
std::cout << "Number is even";
}
else
{
std::cout << "Number is odd";
}
return 0;
}
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∙ 13y ago
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Write c program to find odd or even no?
For any number n you could use * (n % 2 == 0), which would be true for an even number, false for odd For an integer i, a simpler method would be * (i & 1), which would be true for an odd number, false for even
What is odd loop in 'C' program?
odd loop means at least the loop execute once.
How do you write a C plus plus program that will display the first 10 positive prime numbers?
By learning how to program on C+.
Write a program in c plus plus for finding the sum of first 10 even numbers?
int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;
Why when you add 3 odd numbers together you get an odd number as the sum?
Because three odd numbers can be expressed as 2a + 1, 2b + 1 and 2c + 1. Adding these gives 2(a + b + c) + 3: 2(a + b + c) is obviously even, being a multiple of 2, and 3 is equally obviously 1 more than another even number, so your total comprises two even numbers plus 1, ie an odd number.
How do you write a C program to check whether the number is odd or even Ps-using DEV complier?
To write a C program to determine if something is odd or even you need to be a programmer. To write a program in C is complicate and only done by programmers.
If n is an odd integer is n plus 6 odd as well?
Yes. If n is odd, then n + c where c is an even constant will be odd. n + d where d is an odd constant will be even.
How do you make a program that display odd number from one to twenty in c plus plus?
for (int i=1; i<20; i+=2) printf ("%d\n", i);
Create a c plus plus program that displays odd numbers between 15 and 30?
for (int i = 15; i < 30; i += 2) cout << i << endl;
Can you add 2 odd numbers that equal an odd number?
no, b/c you can think of an odd number as an even number plus one. So if you add two odd numbers, you would be adding 2 even numbers plus 2... Let # be even... (#+1) + (#+1) = (#+#) + 2 two even numbers added together are always even
Can you program games with c plus plus?
Yes, you can program games with C++.
Write a program in c that prompt user with following lines add two integers test an integer for odd or even and quit?
write a program in C that prompts the user with the following lines: a) Add two integers c) Compare two integers for the larger t) Test an integers for odd or even q) Quit
C program to accept a sequence of number terminated by zero and sum all odd nos and even nos?
#include <stdio.h> main() { int n, odd=0, even=0; while (scanf("%d",&n)&&(n!=0)) (n%2)?++odd:++even; printf("odd: %d even: %d\n",odd,even); }
Write c program to find odd or even no?
For any number n you could use * (n % 2 == 0), which would be true for an even number, false for odd For an integer i, a simpler method would be * (i & 1), which would be true for an odd number, false for even
How to restart c plus plus program?
Exit the program and relaunch it.
What is odd loop in 'C' program?
odd loop means at least the loop execute once.
How we can write a program in C plus plus that takes a number from the user and prints whether it is even or odd?
#include <iostream> using namespace std; int main() { int x; cout << "Enter a number: "; cin >> x; if(x % 2 == 0) { cout << x << " is even" << endl; } else { cout << x << " is odd" << endl; } char wait; cin >> wait; return 0; }
