Yes. If n is odd, then n + c where c is an even constant will be odd. n + d where d is an odd constant will be even.
Every integer is either even (divisible by 2) or odd (not divisible by 2). Since an even number plus 1 is odd and an odd number plus one is even, because 1 does not divide 2. We know (n + 4) is odd. The next integer is (n + 4 + 1) = (n + 5), because an odd number plus 1 is even, (n + 5) is even. The integer after (n + 5) is (n + 6), since (n + 5) we know is even, (n + 6) must be odd. Since (n + 6) is the smallest integer that is greater than (n + 4) and is odd, so (n + 6) is the next odd integer.
Well, lets say you add 3 and 6, you would get 9 which is odd. How about 7 and 6 is 13 again which is odd so I think the answer would be... Even + Odd = Odd :)
m+6
9
n+6
odd. An even integer is divisible by 2, such as ... -8, -6, -4, -2, 0, 2, 4, 6, 8, and so on. All other integers are odd.
An even number is an integer that is divisible by 2 without leaving a remainder. In other words, when an even number is divided by 2, the result is a whole number. Even numbers can be represented as 2n, where n is an integer. Examples of even numbers include 2, 4, 6, 8, and so on.
1. let n = the odd integer then n + 2 must be the next odd integer 2. n + (n + 2) = 56 3. 2n + 2 = 56 4. 2n = 54 5. n = 27 6. 27 + 2 = 29 is the next odd integer
Odd. If an integer ends in 1, 3, 5, 7, or 9 it is odd. If an integer ends in 0, 2, 4, 6, or 8 it is even.
the integer 25 is an odd number the integer is a composite number 6 is less than 25, so is a deficient number
6 plus 7
The statement is true.