5, 2, and 1, are all going to be factors with and number that 10 is a factor of.
1, 2, 3, 10, and 30 must also be factors of that number.
There are 8. Also, by definition factors must be whole numbers because otherwise every non-zero number is a factor of every number (including prime numbers).
If a number is a multiple of 10, then 2 and 5 must also be factors.
Every number with a factor of 10 must have factors of 2 and 5. This is because 10 can be expressed as 2 x 5. Any number that is a multiple of 10 will have both 2 and 5 as factors, along with any other factors it may have. These two prime factors are essential for a number to have a factor of 10.
Even numbers must have 2 amongst their factors; they may have other even numbers amongst their factors. Odd numbers must not; every factor of an odd number must be odd.
1,2,4,5,10
Various number has factors including 5 and 3 such as 15 and 45.
If a number is divisible by 6, then it must also be divisible by all the factors of 6, because 6 is just a multiple of each of its factors.
No, it is not possible. Every multiple of 21 is a composite number. 21 is a composite number and its factors are 1, 3, 7 and 21(4 factors). Any multiple of 21 must have all the factors of 21. So, every multiple of 21 has at least 4 factors. And a prime number has only two factors so, any multiple of 21 can't be prime.
For a number to be prime, it must have factors, or numbers that go into it, other than 1 and itself. Since 2 goes into every even number, almost every even number is prime. One exception: the number 2. This is because two's only factors are 2 and 1.
1 and 6
The number 27 is an odd number.It is also a composite number, meaning that it factors other than itself and 1.Being an odd number, all of its factors must also be odd numbers.Its factors are 1x27 and 3x9.Because 3x3x3 = 27, then 27 is 3 cubed.