You have to give the context of the problem. It looks like someone copied a question directly off their homework without thinking. Tsk, tsk, tsk.
None.Vertices is a plural term and therefore "a vertices" cannot exist. As a result "a vertices" cannot have any vertices. In fact, it cannot have anything apart from non-existence.
No. Vertices are points. They have no length and so cannot have lines.
(0, -3) is not in any quadrant. I lies on the border between two quadrants. Because zero is not positive or negative, it cannot be defined as in a quadrant
You cannot have a quadrant (a quarter) in a shape that is divided into 9 parts!
A quadrilateral cannot have only three vertices.
No, it cannot.
If the number of vertices is not the same as the number of faces, it cannot be a pyramid.
You cannot have such a shape because either the shapes must meet at an edge or the vertices must be joined by an edge.
Since the number of sides and vertices is different, it cannot be a 2-dimensional shape. The only 3-dimensional shape with 4 vertices is a tetrahedron and that does not have 6 sides. Consequently, there is no such shape.
No, they cannot be. If they were, they would form a straight line, not a triangle!
A shape with four sides and three vertices does not exist in Euclidean geometry. In Euclidean geometry, a shape must have the same number of sides as vertices. Therefore, a shape with four sides would have four vertices.
2 faces can't share the same face, and they cannot share ALL vertices and edges either