You have to give the context of the problem. It looks like someone copied a question directly off their homework without thinking. Tsk, tsk, tsk.
None.Vertices is a plural term and therefore "a vertices" cannot exist. As a result "a vertices" cannot have any vertices. In fact, it cannot have anything apart from non-existence.
No. Vertices are points. They have no length and so cannot have lines.
(0, -3) is not in any quadrant. I lies on the border between two quadrants. Because zero is not positive or negative, it cannot be defined as in a quadrant
You cannot have a quadrant (a quarter) in a shape that is divided into 9 parts!
A quadrilateral cannot have only three vertices.
No, it cannot.
If the number of vertices is not the same as the number of faces, it cannot be a pyramid.
You cannot have such a shape because either the shapes must meet at an edge or the vertices must be joined by an edge.
No, they cannot be. If they were, they would form a straight line, not a triangle!
Since the number of sides and vertices is different, it cannot be a 2-dimensional shape. The only 3-dimensional shape with 4 vertices is a tetrahedron and that does not have 6 sides. Consequently, there is no such shape.
A shape with four sides and three vertices does not exist in Euclidean geometry. In Euclidean geometry, a shape must have the same number of sides as vertices. Therefore, a shape with four sides would have four vertices.
2 faces can't share the same face, and they cannot share ALL vertices and edges either