To find the greatest four-digit number that is divisible by 15, 20, and 25, we need to find the least common multiple (LCM) of these three numbers.
First, let's find the prime factorization of each number:
15 = 3 × 5 20 = 2 × 2 × 5 25 = 5 × 5
The LCM will be the product of the highest powers of each prime factor that appears in any of the numbers:
LCM = 2^2 × 3^1 × 5^3 = 4 × 3 × 125 = 1,500
So, the greatest four-digit number that is divisible by 15, 20, and 25 is 1,500.
Answer: 1,500
If the last two digits of a number are divisible by 4, the whole number is divisible by 4.
yes 72/3 equals 24. an easy way to find out if a number is divisible by three is to add up all the digits. if the sum of the digits is divisible by three, the whole number is divisible by three.
No it is not. To find out:Add the digits in the number (ex.- 1+6+0=7)If 7 is divisible by 9 (it is not) then the whole original number is divisible by nine.Hope i helped!;)
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
Add up the digits. If that total is a multiple of 3, so is the original number.
Divisibility if a number by 3 is not determined by its last digits: instead it is determined by the number's digital root.You get the digital root of a number by adding together all its digits. If the answer is a big number, then find the digital root of the answer. Keep going until you have a number that is smaller than 10. If this number is 3, 6 or 9 (all divisible by 3) then the original number is divisible by 3. And it not, it is not.
To determine what number makes 371 divisible by 3, we need to sum the digits of 371: 3 + 7 + 1 = 11. To be divisible by 3, the sum of the digits must also be divisible by 3. Since 11 is not divisible by 3, we need to find the number that, when added to 11, results in a sum divisible by 3. The next multiple of 3 greater than 11 is 12, so the number that makes 371 divisible by 3 is 1.
Add up the digits in the number. If the total is a multiple of 3, the entire number will be a multiple of 3.
Yes, it is true 558/3 = 186 To find out if a number is divisible by 3, add the digits; if the sum is divisible by 3, so is the number 5+5+8 = 18 which is divisible by 3
Take the number 3336. You know it's divisible by 1 because everything is. You know it's divisible by 2 because it's even. You know it's divisible by 3 because the digits add up to a multiple of 3 and you know it's divisible by 4 because the last two digits are divisible by 4. So you've found at least four factors: 1,2,3 and 4.
To determine which number is divisible by both 9 and 4, we need to check if the number is divisible by both 9 and 4 simultaneously. A number is divisible by 9 if the sum of its digits is divisible by 9. A number is divisible by 4 if the number formed by its last two digits is divisible by 4. Among the options provided, only option D, 9126, meets both criteria as the sum of its digits is 18 (divisible by 9) and the number formed by its last two digits is 26 (divisible by 4).
To find out if 1859 is a prime number, use the rules of division:1859 is not an even number, so it is not divisible by 2.The digits of 1859 add up to a number that is divisible by 3, so it is not divisible by 3.The last two digits (59) is not divisible by 4, so neither is 1859.The last digit is not 5, so it is not divisible by 5.1859 is not divisible by 2 and it is not divisible by 3, so it is not divisible by 6.When you double the last digit (9 doubled is 18), and subtract that number from the rest of the number (859 - 18 = 841), if the answer is 0 or divisible by 7, the number itself is divisible by 7. If you can't readily tell if the number is divisible by 7, you can do the steps again. Starting with 841, doubling the 1 is still 1, so take 1 away from 84 to get 83. 83 is not divisible by 7, so neither is 1859.The last three digits (859) are not divisible by 8, so 1859 is not divisible by 8.If the sum of the digits is divisible by 9, the number is divisible by 9. The sum of the digits is 23, which is not divisible by 9.1859 does not end with a 0, so it is not divisible by 10.If the sum of every second digit (8 + 9) minus the sum of the other digits (1 + 5) equals 0 or is divisible by 11, the number itself is divisible by 11. 17 - 6 = 11, so 1859 is divisible by 11.Since 1859 is divisible by 11, it is a composite number (a number that has at least three factors: 1, the number itself, and at least one oher factor).