0
Best Answer
Let the odd integers be , n, n+2 & n+4
Hence
n + (n+2) + (n +4) = 471
Add LHS
3n + 6 = 471
Subtract '6' from both sides
3n = 465
Divide both sides by '3'
n = 155
n + 2 = 157
n + 4 = 159
Hence the integers are 155,157 & 159.
This answer is:
More answers
155 + 157 + 159
This answer is:
Add your answer:
Earn +20 ptsQ: Find three consecutive odd integers whose sum is 471?
Write your answer...
Submit
Still have questions?
Related questions
What is the sum of three consecutive integers is 88?
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43
Is it possible to find three consecutive even integers whose sum is 40?
No. There is no set of three consecutive even integers with a sum of 40.
Find three consecutive integers whose sum is 51?
The integers are 16, 17 and 18.
Find three consecutive integers whose sum is 60?
The integers are 19, 20 and 21.
Find three consecutive integers whose sum is -108?
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
Find three consecutive odd integers whose sum is 135?
Those three odd integers are 43, 45, and 47.
Find three consecutive odd integers whose sum is (-75)?
Those three odd integers are 43, 45, and 47.
Find three consecutive even integers whose sum is 72?
The even integers are 22, 24 and 26.
Find three consecutive integers whose sum is 300?
99, 100, and 101
Find three consecutive integers whose sum is 96?
31, 32 and 33
Find three consecutive integers whose sum is -30?
-9, -10 and -11.
Find three consecutive integers whose sum is -42?
They are -15, -14 and -13.
Copyright ©2024 Infospace Holdings LLC, A System1 Company. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Answers.