Let the odd integers be , n, n+2 & n+4
Hence
n + (n+2) + (n +4) = 471
Add LHS
3n + 6 = 471
Subtract '6' from both sides
3n = 465
Divide both sides by '3'
n = 155
n + 2 = 157
n + 4 = 159
Hence the integers are 155,157 & 159.
No. There is no set of three consecutive even integers with a sum of 40.
The integers are 16, 17 and 18.
The integers are 19, 20 and 21.
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
Those three odd integers are 43, 45, and 47.
Those three odd integers are 43, 45, and 47.
The even integers are 22, 24 and 26.
99, 100, and 101
They are -15, -14 and -13.
31, 32 and 33
a+(a+d)+(a+2d)=-15
-6, -7, and -8.