find three consecutive odd integers whose sum is 471?

Answer 1

Let the odd integers be , n, n+2 & n+4

Hence

n + (n+2) + (n +4) = 471

Add LHS

3n + 6 = 471

Subtract '6' from both sides

3n = 465

Divide both sides by '3'

n = 155

n + 2 = 157

n + 4 = 159

Hence the integers are 155,157 & 159.

Answer 2

155 + 157 + 159