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Find A and B if 36A2B is a multiple of 9 and a multiple of 4 A does not equal B?
Wiki User
∙ 12y ago
You need to find a product of 9 & 4 which is 36. A2B mean its a 3 digit number that has a 2 in the middle.
Now, you need to multiply 36 by 10 to make it a 3 digit number which give you 360. Since 6 is the middle number and its not 2, then 360 is not right. From this point, you keep adding 360 to to original number which is 360 until you get a number that is divisible by both 4 & 9.
So, 360 + 360 = 720. Here, the 2 is the middle number so this is a good start.
Now, 4 goes into 720 (180 times) and 9 goes into 720 (80 times). So A = 7 and B = 0. The answer is 36720 (this number is divisible by both 4 & 9.
Wiki User
∙ 12y ago
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