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[object Object]
The volume is (6 x 3 x 1) = 18 cm3 . The density is (whatever amount of mass is contained in 1 cm3 ) per cm3 , or (1/18 of the mass of the total solid you described) per cm3 .
If it is for volume, then you first need a graduated cylinder. Put water in there, then put an object in there, and then mark and record the difference. If it is a 12 milliliter (mL) difference, then it is 12 cm3, since 1 mL = 1 cm3
1/3 gram per CC
To find the angular size, we need to convert the distance to the object into radians. 4 yards is approximately 12 feet or 144 inches. The angular size can be calculated as the diameter of the object (1 inch) divided by the distance to the object (144 inches), which equals approximately 0.0069 radians.
[object Object]
(50g)/(15g/cm3)=3.333...cm3 or 3 1/3 cm3
1 ml by Kevin xu from sedomocha middle school
No. 1 m3 = (100cm)3 = 1003 cm3 = 1000000 cm3 So 0.01 m3 = 0.01*(100cm)3 = 0.01*1003 cm3 = 10000 cm3
1. Measure the dimensions of the object 2. Calculate the volume, in cm3 3. Weigh the object, in g 4. The density is the ratio between the mass and the volume, in g/cm3. For small objects you can use special densimetric balances.
It will sink. Water has a density of 1 gm/cm3.
Its density is 1 g/cm3
1 cm3 (or 1 mL, they are equivalent)
The volume is (6 x 3 x 1) = 18 cm3 . The density is (whatever amount of mass is contained in 1 cm3 ) per cm3 , or (1/18 of the mass of the total solid you described) per cm3 .
The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7
1 cm3 is 0.001liters.
The density is important; for floating an object must have a density under the water density (1 g/cm3).