(50g)/(15g/cm3)=3.333...cm3
or 3 1/3 cm3
Note 5cm isn't a volume it is a length therefore for the answer we are assuming the volume is 5cm3 Density = mass/volume Density = 15g/5cm3 = 0.015kg/0.000005m3 Density = 3g/cm3 or in SI units 3,000kg/m3
Ethanol (USP grade) has a density of 0.810. From here we have to use the formula: d=m/v, where d is density, m, mass and v, volume. Solving for volume, we have v=m/d, therefore: v= 15/0.810 = 18.52 mL of ethanol are equivalent to 15g.
The formula unit of sodium chloride has the formula NaCl, showing that each molecular unit contains one atom of each of its constituent elements. Therefore, the mass of the formula unit is 23 plus 35 or 57 amu. Each amu for a compound contains Avagadro's number of molecules. Therefore, the answer to the problem is about (15/57) X 6.022 X 1023 = 4.3 X 1022.
Fluorine, at 19 atomic mass units, is the only halogen gas that fits that requirement.
That is about 2.9 teaspoons.
Density = Mass/Volume = 15/60 = 0.25 grams per millilitre.
Density = Mass/Volume = 15/10 = 1.5 g per mL
density = mass/volume = 15g/2mL = 7.5g/mL
Note 5cm isn't a volume it is a length therefore for the answer we are assuming the volume is 5cm3 Density = mass/volume Density = 15g/5cm3 = 0.015kg/0.000005m3 Density = 3g/cm3 or in SI units 3,000kg/m3
density = mass/volume = 150g/9.8cm3 =~15.3g/cm3 =~15g/cm3 (assuming volume of 9.8cm means 9.8 cubic centimeters)
15g/cm^3
m = mass rho = density V = volume rho = m/V m = rho * V = (15 g/cm^3) * (10 cm^3) = 150 g
Ethanol (USP grade) has a density of 0.810. From here we have to use the formula: d=m/v, where d is density, m, mass and v, volume. Solving for volume, we have v=m/d, therefore: v= 15/0.810 = 18.52 mL of ethanol are equivalent to 15g.
Denisty = mass / volume Density = 15g / 5cm3 Density = 3g per cm3 Once you know that the units of Density is g/cm3, you can use this to work out that you need to divide the mass (g) by volume (cm3) as can be seen in the units. This works for any equation you know the units for, like speed: Speed = m/s (meters/seconds) = distance/time
15g/cm3
15g/cm3
Before we can go on to find the density of the carbon nucleus, we must find its mass. The given molar mass, which is the mass of 1 mole of a substance, indicates there's 12.00 grams of carbon for every 1 mole of carbon. What the question wants to know is the density of 1 carbon atom. Before we proceed to finding the carbon atom's density, the mass for 1 carbon atom must be found. To achieve this, we must divide the molar mass by Avogadro's number (aka Avogadro constant), or how many molecules are in 1 mole of a substance.Mass per atom = molar mass/Avogadro's number= 12.00 g mol-1/6.02 x 1023 mol= 1.99 x 10-23gNow we can proceed to find the density of the carbon nucleus, since we now know the mass for 1 carbon atom.Density= mass/volume= 1.99 x 10-23g/9.9 x 10-39mL= 2.0 x 10-15g/mL OR 2.0 x 10-15g/cm31 mL is equivalent to 1 g/cm3, making these 2 units interchangeable.By the way, another way to write g mol-1 is g/mol (the -1 indicates the divisor or can be read as "per").