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This is an arithmetic sequence with the first term t1 = 1, and the common difference d = 6. So we can use the formula of finding the nth term of an arithmetic sequence, tn = t1 + (n - 1)d, to find the required 30th term.
tn = t1 + (n - 1)d
t30 = 1 + (30 - 1)6 = 175
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