This is an arithmetic sequence with the first term t1 = 1, and the common difference d = 6. So we can use the formula of finding the nth term of an arithmetic sequence, tn = t1 + (n - 1)d, to find the required 30th term.
tn = t1 + (n - 1)d
t30 = 1 + (30 - 1)6 = 175
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Well, honey, if the nth term is 3n-1, then all you gotta do is plug in n=30 and do the math. So, the 30th term would be 3(30)-1, which equals 89. There you have it, sweet cheeks, the 30th term of that sequence is 89.
36
82
The answer is given in the following sentence.
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.