I will assume that you mean to ask, "What is the arc length of curve C from t=0 to t=1 if curve C is defined parametrically by x=1+2e^t and y=e^t?"
I can answer this question.
dx/dt=2e^t and dy/dt=e^t.
Arc length = a∫b √[(dx/dt)2+(dy/dt)^2]
= 0∫1 √[4e^(2t)+e^(2t)]dt
= 0∫1 √[5e^(2t)]dt.
= 0∫1 [(√5)(e^t)]dt
= √5 x (e^1-e^0)
= √5 x (e-1)
= e√5-√5.
Difficult? Maybe. Fun? Hopefully. Accurate? Definitely!
4.9
6.2
12.9
There is no direct relationship between the volume (length*breadth*height) and weight. A given volume of air and the same volume of lead will have ver different weights.
16.7 is d ans
The radius of curvature is given by(1)where is the curvature. At a given point on a curve, is the radius of the osculating circle. The symbol is sometimes used instead of to denote the radius of curvature (e.g., Lawrence 1972, p. 4).Let and be given parametrically by(2) (3)then(4)where and . Similarly, if the curve is written in the form , then the radius of curvature is given by
R = radius c = chord length s = curve length c = 2Rsin(s/2R) you can solve for radius by trial and error as this is a transcendental equation
Area divided by width equals length
Assuming that the given demand curve is a rectangular hyperbola, total expenditure (i.e. rectangular area or Q*P) is the same for each point on the length of the curve. Next we use the demand function to determine the total expenditure value as Q=1/P=>Q*P=1, and we have consequently a demand curve of unitary elasticity.
4.9
6.2
12.9
In order to find length BC the length of AC or length of the hypotenuse must be given
8.3
16.1
depth equals volume divided by length times width
Length (L) equals area (A) divided by width (W); or L = A / W.