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take the derivative


critical number when x=pi/4

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โˆ™ 2009-11-05 04:46:20
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Q: Find the critical numbers of sinx plus cosx?
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How do you simplify cosx plus sinx tanx?

to simplify Cosx=Sinx Tanx you should remember your fundamental and pythagorean identities.. Cosx + Sinx Tanx Cosx + Sinx (Sinx/Cosx) <---------- From Tanx= Sinx/Cosx Cosx + Sin2x/ Cos x <------------- do the LCD Cosx (Cosx/Cosx) + Sin2x/Cosx (Cos2x+Sin2x)/Cosx 1/Cosx <--------- From Sin2x + Cos2x =1 or Secx <-------- answer Comment if you have questions...:))

Prove this identity 1 plus cosx divide by sinx equals sinx divide by 1-cosx?


Differentiation of sin x 1 plus cosx?

The differentiation of sin x plus cosx is cos (x)-sin(x).

What is the differentiation of sin x over 1 plus cosx?

The derivative is 1/(1 + cosx)

Differentiation of sin x 1 plus cosx-?

The differentiation of sin x plus cosx, yields cos(x)-sin(x).

How do you solve 1 minus cosx divided by sinx plus sinx divided by 1 minus cosx to get 2cscx?

(1-cosx)/sinx + sinx/(1- cosx) = [(1 - cosx)*(1 - cosx) + sinx*sinx]/[sinx*(1-cosx)] = [1 - 2cosx + cos2x + sin2x]/[sinx*(1-cosx)] = [2 - 2cosx]/[sinx*(1-cosx)] = [2*(1-cosx)]/[sinx*(1-cosx)] = 2/sinx = 2cosecx

What is 1 minus cosx divided by since minus since divided by 1 plus cosx?


How does secx plus 1 divided by cotx equal 1 plus sinx divided by cosx?

secx = 1/cosxand 1/cotx = tanx, therefore1/cosx + tanx = 1 + sinx/cosx, andsin/cos = tanx, therefore1/cosx + tanx = 1 + tanx, therefore1/cosx = 1, therfore1 = cosx.So, therfore, it is not neccesarily true.But if you meansecx plus 1 divided by cotx equals (1 plus sinx) divided by cosx(this is probably what you mean) Let's start over!secx = 1/cosxand 1/cotx = tanx, therefore1/cosx + tanx = (1+sinx)/cosx therefore1/cosx + tanx = 1/cosx + sinx/cosxsinx/cosx = tanx therfore1/cosx + tanx = 1/cosx + tanxDo you think this is correct? Subtract both sides by 1/cosx + tanx:0 = 0So, therefore, this is correct!(BTW, I'm in Grade 6! :P)

What is sinx plus cosx plus cotx simplified?

There is no sensible or useful simplification.

What is the derivative of 1 plus cosx?

negative sin(x)

Integral of cos2x log cosx-sinx coax plus since?

it is not possible to get the Integral of cos2x log cosx-sinx coax plus since there are no symbols given in the equation.

Sinx plus cosx equals 0?

x = 3pi/4

Does sin x tan x plus cos x equals tan x?

NO, sinxtanx=sinxsinx/cosx since tanx is sinx/cosx this is sin^2xcosx now add cosx cosx(sin^2x+1) after factoring Does this equal tanx? No, since this would require tanx to equal cosx(sin^2x+1) and it does not.

Cos x plus sin x equals 0?

cosx + sinx = 0 when sinx = -cosx. By dividing both sides by cosx you get: sinx/cosx = -1 tanx = -1 The values where tanx = -1 are 3pi/4, 7pi/4, etc. Those are equivalent to 135 degrees, 315 degrees, etc.

How do you integrate open bracket x plus 1 close bracket cosx?

Try integration by parts, (twice, I think) with u=(x+1) and dv/dx=cosx

How do you simplify tanx plus tany per cosx plus coty?

(tan x- 1)/ (1+tan x)

How do you factor x plus cosx?

x + cos x can't be factored or otherwise simplified.

How do you prove the following equation the quantity of sin theta divided by 1 minus cos theta minus the quantity 1 plus cos theta divided by sin theta equals 0?

You will have to bear with the angle being represented by x because this browser will not allow characters from other alphabets!sin^2x + cos^2x = 1=> sin^2x = 1 - cos^x = (1 + cosx)(1 - cosx)Divide both sides by sinx (assuming that sinx is not zero).=> sinx = (1 + cosx)(1 - cosx)/sinxDivide both sides by (1 - cosx)=> sinx/(1 - cosx) = (1 + cosx)/sinx=> sinx/(1 - cosx) - (1 + cosx)/sinx = 0

What is (1 plus cos x)(1- cos x)?

(1+cosx)(1-cosx)= 1 +cosx - cosx -cos^2x (where ^2 means squared) = 1-cos^2x = sin^2x (sin squared x)

What are the critical numbers of 4 x to the third power minus 60 x squared plus 288 x minus 432?

To find critical numbers or critical points, find out where the derivative equals 0.The function is 4x3-60x2+288x-432.It's derivative then is 12x2-120x+288, set that equal to 0 to find critical points: 12x2-120x+288 = 0Factor out a 12:12(x2-10+24) = 0Divide both sides by 12:x2-10+24 = 0Factor:(x-6)(x-4) = 0(x-6) = 0 or (x-4) = 0x = 6 or x = 4The critical numbers are 6 and 4.

How to find a whole number?

The whole numbers include the counting numbers, plus zero.

Parenthesis 1 plus tanx end parenthesis divided by sinx equals cscx plus secx?

(1 + tanx)/sinxMultiply by sinx/sinxsinx + tanxsinxDivide by sin2x (1/sin2x) = cscxcscx + tan(x)csc(x)tanx = sinx/cosx and cscx = 1/sinxcscx + (sinx/cosx)(1/sinx)sinx cancels outcscx + 1/cosx1/cosx = secxcscx + secx

Is the solution of 1 plus cosx equals 0 is ฯ€ plus 2kฯ€?

Yes, that looks good. That's 180 degrees plus every multiple of 360 degrees more.

How do you integrate sinx divide sinx plus cosx?


How do you express sin x plus cos x divided by cos x in terms of tan x?

(sin x + cos x) / cosx = sin x / cos x + cosx / cos x = tan x + 1