0
to simplify Cosx=Sinx Tanx you should remember your fundamental and pythagorean identities..
Cosx + Sinx Tanx
Cosx + Sinx (Sinx/Cosx) <---------- From Tanx= Sinx/Cosx
Cosx + Sin2x/ Cos x <------------- do the LCD
Cosx (Cosx/Cosx) + Sin2x/Cosx
(Cos2x+Sin2x)/Cosx
1/Cosx <--------- From Sin2x + Cos2x =1
or Secx <-------- answer
Comment if you have questions...:))
Still curious? Ask our experts.
Chat with our AI personalities
Jordan
Maxine
DevinAdd your answer:
Earn +20 pts
Cos x plus sin x equals 0?
cosx + sinx = 0 when sinx = -cosx. By dividing both sides by cosx you get: sinx/cosx = -1 tanx = -1 The values where tanx = -1 are 3pi/4, 7pi/4, etc. Those are equivalent to 135 degrees, 315 degrees, etc.
Does sin x tan x plus cos x equals tan x?
NO, sinxtanx=sinxsinx/cosx since tanx is sinx/cosx this is sin^2xcosx now add cosx cosx(sin^2x+1) after factoring Does this equal tanx? No, since this would require tanx to equal cosx(sin^2x+1) and it does not.
What is the limit of x- sin x cos x over tan x -x as x tends to zero?
It is minus 1 I did this: sinx/cos x = tan x sinx x = cosx tanx you have (x - sinxcosx) / (tanx -x) (x- cos^2 x tan x)/(tanx -x) let x =0 -cos^2 x (tanx) /tanx = -cos^x -cos^2 (0) = -1
Why tan x graph is continuous within its domain and is not continuous out of the domain?
we do not check if a function is continuous or not outside it's domain."first, f has to be defined at c."Tanx is not defined where cosx=0 .ie x=pi/2 , 3pi/2 etcill try to help more here.what domain means is what can you put into a function, whereas range, which i am sure you have heard of as well, just means what you can get out of a function. that being said, lets look further into the graph of tanx. when we do, we see that the graph is discontinuous at pi/2. the reason for this is because tanx is equivalent to sinx/cosx. because of this relationship, when you put pi/2 in for x in sinx/cosx, you end up with cosx=0 which makes your denominator zero, which is undefined, which makes your graph discontinuous. because of that, you cannot put pi/2 in for x in tanx, and since the domain is what you can put into an equation, pi/2 which causes a discontinuity is not included in the domain. basicly, wherever a graph is discontinuous, it wont be included in the domain because you cant put stuff in that will make your graph discontinuous
How do you differentiate 2tanx?
Oh, dude, it's like super easy. So, to differentiate 2tanx, you just use the chain rule. You take the derivative of tanx, which is sec^2x, and then multiply it by the derivative of the inside function, which is just 2. So, the answer is 2sec^2x. Easy peasy, right?
