Without an equality sign and not knowing the plus or minus values of some of the given terms it can't be considered to be a straight line equation.
In general parallel equations have the same slope but different y intercepts.
i am cute
It has no equation as such because plotting the line on a grid will produce a vertical straight line parallel to the y axis.
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
Without an equality sign it is not an equation but when a straight line equation is parallel to another straight line the slope remains the same but the y intercept is different
To find the equation of a line parallel to another line, we need the same direction vector. The direction vector of the given line is (2, -3). Therefore, the equation of the line parallel to it passing through (-1, 3) is x = -1 + 2t and y = 3 - 3t, where t is a parameter.
i am cute
It has no equation as such because plotting the line on a grid will produce a vertical straight line parallel to the y axis.
In 2-dimensional co-ordinate geometry, a line parallel to the y axis has the equation x = c where c is a constant.
5
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
find equation of the line. write equation in slope intercept form. (5,5) parallel line (3,13) and (12,13)
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
The gradient of the line y = -3 is 0. So any parallel line has the equation y = c.Since it goes though the point (2, 6), c = 6 and so the equation is y = 6.
Without an equality sign it is not an equation but when a straight line equation is parallel to another straight line the slope remains the same but the y intercept is different
When the equation of a line is parallel to another line the slope remains the same but the y intercept changes
what
To find the equation of a line parallel to another line, we need the same direction vector. The direction vector of the given line is (2, -3). Therefore, the equation of the line parallel to it passing through (-1, 3) is x = -1 + 2t and y = 3 - 3t, where t is a parameter.