140
A regular pentagon is convex. By taking a regular pentagon and shortening or lengthening one or more sides, an infinite number of possible convex pentagons can be created. A convex polygon is defined as a polygon such that all internal angles are less than or equal to 180 degrees, and a line segment drawn between any two vertices remains inside the polygon. It is possible to have non-convex (concave) pentagons; there are infinite number possible ways to do this, too.
5 sides and it is a regular pentagon
exterior angle of regular polygon is always 360 divided by number of sides, so number of sides = 360 divided by exterior angle, in this case 360/32.72 ie 11.
Interior angles 178 so exterior angles 2. Number of sides of any regular polygon = 360/exterior angle You polygon has 180 sides. Bet you're glad you didn't have to sketch it!
An obtuse triangle has 3 sides.
No, as long as the polygon is convex.
A regular pentagon is convex. By taking a regular pentagon and shortening or lengthening one or more sides, an infinite number of possible convex pentagons can be created. A convex polygon is defined as a polygon such that all internal angles are less than or equal to 180 degrees, and a line segment drawn between any two vertices remains inside the polygon. It is possible to have non-convex (concave) pentagons; there are infinite number possible ways to do this, too.
Use this form to work out the problem: (n - 2)180° where n is the number of sides Suppose that we have a regular polygon. This is the example of a convex polygon. Given that we have a 5-sided convex polygon, we obtain: (5 - 2)180° = 3 * 180° = 540°
No. In a convex polygon the sum of the interior angles is (n-2)*180 deg where n is the number of interior angles. In a non-convex polygon this is not necessarily true.
The answer depends on the number of sides in the polygon.
A concave polygon cannot be regular because regularity requires all angles (and sides)to be of equal measure. Even if you drop the requirement of regularity, there cannot be a concave triangle.
The sum of the interior angles of a convex polygon is 180*(n-2) degrees, where n is the number of vertices and angles.That depends on how, many sides the polygon has.-- Subtract 2 from the number of sides.-- Multiply that number by 180.-- The result is the sum of the interior angles in that polygon.It doesn't matter whether the sides of the polygon are all equal ("regular" polygon), orwhether it's all funny and squashed. You only need to know the number of sides it has.
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. Divide that by the number of sides.
CHARACTERISTICS OF REGULAR POLYGON WHICH CAN TESSELLATE:1. Polygon must be regular convex polygon which means that every angle and sides are equal in measurement.2. Measurement of every corner angle must be divisible by 360, thus, (n-2) | 2n.3. Polygon must have the number of sides of either 3, 4, or 6.
Remember that the internal angle of a regular convex polygon is (n - 2) * 180 degrees / n, where n is the number of sides in the polygon. Also remember that the external angle of a regular convex polygon is 180 degrees minus the internal angle a polygon. So the external angle of a polygon is 180 - ((n - 2) * 180 / n). The sum of the angles will be the external angle multiplied by n, or: (180 - ((n - 2) * 180) / n ) * n = 180 * n - (n - 2) * 180 Please note that I only proved this for regular polygons, but this formula should also extend to irregular convex polygons too. If a teacher asks you for a proof, then this will be insufficient.
There is no maximum number for a an irregular concave polygon. If it must be convex, then there is a maximum of 3.
Number of lines of symmetry = Number of sides of the regular polygon