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The sum of the interior angles of a convex polygon is 180*(n-2) degrees, where n is the number of vertices and angles.
That depends on how, many sides the polygon has.
-- Subtract 2 from the number of sides.
-- Multiply that number by 180.
-- The result is the sum of the interior angles in that polygon.
It doesn't matter whether the sides of the polygon are all equal ("regular" polygon), or
whether it's all funny and squashed. You only need to know the number of sides it has.
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A convex polygon has 6 sides what is the sum of the measure of its interior angles?
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
Is the sum of interior angles of a convex polygon the same as a non convex polygon?
Yes, the angle sums will be the same regardless of whether or not it is a convex polygon.
What is the sum of the interior angle of a 13-sided polygon?
The sum of the interior angles of a triangle is 180 deg. For a convex polygon with n sides we can divide it to n-2 triangles. So the answer, if the polygon is convex, is (13-2)*180= 1980 deg * * * * * The polygon need not be convex. The formula for the sum of the interior angles is valid as long as the polygon is simple - that it, its sides do not cross each other inside the polygon.
What is the polygon if the sum of the interior angles if a convex polygon was 5940?
It is: (5940+360)/180 = 35 sides
What is the sum of the measures of the exterior and interior angles of a convex 24-gon?
The sum of the exterior angles of any convex polygon is always 360 degrees. The sum of the interior angles of any convex n-gon is (n-2) * 180 degrees, because any convex n-gon can be represented as n-2 triangles, and the sum of the interior angles of a triangle is 180 degrees.
