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Find the possible value or values of y in the quadratic equation 4-4y-y2 0?
Updated: 9/25/2023
SamNesbittgp6936
Lvl 1
∙ 8y agoBest Answer
Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. Assuming that the equation is
4 - 4y + y^2 = 0, the two values of y are
-2-2*sqrt(2) = -4.8284, approx, and
-2+2*sqrt(2) = 0.8284, approx.
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∙ 8y agoThis answer is:
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