Find the prime factorization of the number 1998?

Answer 1

1998 is an even number, so it's divisible by 2; 1998/2 = 999. If you add up the numbers of that result, 9 + 9 + 9, you get 27. Since 27 is divisible by 3, 999 must also be divisible by 3; 999/3 = 333. Once again, if you add up the numbers of that result, 3 + 3 + 3, you get 9, and since 9 is divisible by 3, 333 must be too; 333/3 = 111. Again, if you add up the numbers of that result, 1 + 1 + 1, you get 3, so 111 must also be divisible by 3; 111/3 = 37. Our factors are now 2 X 3 X 3 X 3 X 37, which are all prime numbers. Thus, the prime factorization of 1998 is 2 X 33 X 37.