Sum = 42 Count = 6 Mean = Sum/Count = 42/6 = 7
-23 is the sum of -32 and 9
It is: 3+6 = 9
9 and 6 9-6 = 3 92+62 = 117
The sum of 9 and -6 is 3.
six, nine 9 + 6 = 15 (sum) 9 - 6 = 3 (difference) 9 x 6 = 54 (product)
There are 36 permutations of two dice. Of these, 9 have a sum of 5 or 6, so the probability of rolling a sum of 5 or 6 on two dice is 9 in 36, or 1 in 9, or about 0.1111.
6+9=15 6*9=54
8. To find 'the sum of' something, is just to add them together really. Eg - The sum of 9 + 3 = 12.
3 and 9 Difference: 9-3=6 Sum: 9+3=12
Sum = 42 Count = 6 Mean = Sum/Count = 42/6 = 7
9
9 and 6
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
9
-23 is the sum of -32 and 9
the sum is the answer to an addition problem e.g.4+5=9 9 is the sum