6+9=15
6*9=54
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
The numbers are 13 and 8 The product is 104
Sum of squares? Product?
272 is the maximum possible.
find two positive numbers whose product is a maximum. 1.) the sum is s.
the product of 3 whole numbers is 5. Their sum is 7. what are the numbers
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
A "sum" is a process that involves at least two numbers, and a "product" is also a process that involves at least two numbers. Your question talks about a 'sum' and a 'product', so we expect to find at least four numbers to work with. But there are only two numbers in the whole question. So, to put it gently, we find the question to be somewhat deficient, and lacking an answer.
Not possible in whole numbers
Not whole numbers, no.
2x2=42+2=4I tried negative numbers and didn't find any.
20 x 21 = 420
3 and 84.
They are 12 and 15
The numbers are 13 and 8 The product is 104
12 and 3.
6 and 4