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The 3 consecutive odd positive integers are 7, 9 and 11.

Q: Find three consecutive odd positive integers so that the product of the first two is three less than six times the largest?

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The product is 30.

It is 23.

The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1

13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.

The numbers are 8 and 9.

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The two consecutive positive integers whose product is 380 are 19 x 20.

There are no two consecutive integers, negative or positive, whose product is 440.

8 & 9

the two consecutive positive integers whose product is 380 19 20

The product is 30.

It is 23.

The product of 2 consecutive positive number is 48. Find the 2 numbers

The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1

13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.

The numbers are 8 and 9.

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There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.