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The product of 2 consecutive positive number is 48. Find the 2 numbers

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6.

Q: The product of 2 positive consecutive even integers is 48 What is the smaller number?

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The numbers are 11, 13, 15 and 17.

4,6,8,10

The smaller of the two numbers is 31.

Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.

11, 13, 15 and 17(143 is 112 less than 255)The equation is (A)(A+2) = (A+4)(A+6) - 112A2 + 2A = A2 +10A +24 -1122A = 10A - 888A = 88A = 112,5,6

Related questions

It is 23.

13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.

48 = 6 x 8, so the smaller is 6.

Smaller number is '6'

You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210

The numbers are 11, 13, 15 and 17.

-1

the answer is 6

They are 6, 8, 10 and 12.

4,6,8,10

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

No two consecutive integers can add up to 98.No three consecutive integers can add up to 98.But 23, 24, 25, and 26 can.