Q: Find two consecutive odd integers whose sum is 512?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The prime factorization of 512 is 29. There are infinite ways to get 512 as a sum or quotient of positive integers.

384.5 units squared.

12 23 512 as integers 5/12, 1/2, 2/3 as fractions 5/12, 6/12, 8/12

There is only one solution, which comprises the single number 512.

2

Related questions

255 and 257

The prime factorization of 512 is 29. There are infinite ways to get 512 as a sum or quotient of positive integers.

512 and 6910 are integers so their sum is an integer, not an improper fraction.

The least common factor of any set of integers is 1.

8 For a cube, all sides are the same, thus: Side_length3 = 512 => Side_length = cube_root(512) = 8

8

Volume = e3 where e is the edge length. So, 83 = 512 cubic cm

512

384.5 units squared.

12 23 512 as integers 5/12, 1/2, 2/3 as fractions 5/12, 6/12, 8/12

There is only one solution, which comprises the single number 512.

The edge length is: 8 units.