Q: Find two consecutive odd integers whose sum is 512?

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The prime factorization of 512 is 29. There are infinite ways to get 512 as a sum or quotient of positive integers.

12 23 512 as integers 5/12, 1/2, 2/3 as fractions 5/12, 6/12, 8/12

384.5 units squared.

There is only one solution, which comprises the single number 512.

2

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255 and 257

The prime factorization of 512 is 29. There are infinite ways to get 512 as a sum or quotient of positive integers.

512 and 6910 are integers so their sum is an integer, not an improper fraction.

The least common factor of any set of integers is 1.

8 For a cube, all sides are the same, thus: Side_length3 = 512 => Side_length = cube_root(512) = 8

8

Volume = e3 where e is the edge length. So, 83 = 512 cubic cm

512

12 23 512 as integers 5/12, 1/2, 2/3 as fractions 5/12, 6/12, 8/12

384.5 units squared.

The volume of a cube is calculated by cubing the length of one of its sides. In this case, the edge length of the cube is 512 units, so the volume would be 512 * 512 * 512 = 134,217,728 cubic units.

There is only one solution, which comprises the single number 512.