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Q: Find two whole numbers whose product is 147 and whose quotient is 3?

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36

7 & 21

3 and 84.

-42.285 and -7.047

7 and 21 equal 147 and 7x3= 21 so yeah

49 and 8

Not whole numbers, no.

How about: 10 and 150

2 and 9

10 and 28

50 and 30

They are: 2 and 140

1 and 2, whose product is 2.

They are 2 and 140 because their LCM is 140 and their product is 280

-21

They are: 32*33 = 1056

34 and 36

168.

How about: 2*3*16 = 96

10 and 12

That's a factor pair.

For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.

33X34=1122 34-33=1

6 and 4

Numbers whose product is one is called multiplicative inverses.