10 and 28
Three and Seven
To find the LCM, you multiply the numbers together and then divide by the HCF. In this case, we don't know the numbers, but we have the HCF (13) and we have the product of the numbers (1690). Thus all you do is divide 1690 by 13 to get: 1690/13 = 130 And thus the LCM of two numbers whose hcf is 13 and product is 1690 is 130.
13 and 5 13+5=18 13x5=65
the two smallest numbers are 49 and 14
If you are looking for two prime numbers whose difference is 1, then the numbers have to be 1 & 3.
They are: 2 and 140
3 and 84.
They are 2 and 140 because their LCM is 140 and their product is 280
10 and 12
20 x 21 = 420
19
xy = 147 x/y = 3 x = 21 y = 7
find two positive numbers whose product is a maximum. 1.) the sum is s.
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
The numbers are 18 and 20.
10 and 3
9 and 6