It can't be done. There are an infinite number of circles with a specific radius and which go through a specific point. What you need is the centre of the circle.
If you have two points that the circle crosses, then you can narrow it down to two possible circles.
If you have three points that the circle crosses, then you can narrow the list of possible circles down to a single circle.
But without the information above, it's impossible.
The area of a circle is given by: pi multiplied by the square of the radius. So if the radius is 15, the area is 225pi (225 is 15 squared)
c=TT R Given the area, the radius = square root (area / Pi). Given the circumference, the radius = circumf/ 2Pi.
The equation of a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this case, since the radius is 10, the equation becomes ( x^2 + y^2 = 10^2 ). Therefore, the equation of the circle is ( x^2 + y^2 = 100 ).
The circumference of a circle is given by the equation C=2*pi*r (r being the circle's radius). So, the circumference you're looking for is 30.35 cm.
The equation of a circle centered at the origin (0, 0) with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). For a circle with a radius of 3, the equation becomes ( x^2 + y^2 = 3^2 ), which simplifies to ( x^2 + y^2 = 9 ).
To find the standard equation for a circle centered at the origin, we use the distance formula to define the radius. The equation is derived from the relationship that the distance from any point ((x, y)) on the circle to the center ((0, 0)) is equal to the radius (r). Thus, the standard equation of the circle is given by (x^2 + y^2 = r^2). Here, (r) is the radius of the circle.
2 pi rthis is the equation of the circumference of a circle. just multiply out 2 times pi(3.14159) times the radius that you were given.
multiple the diameter by 2 to get the radius, then use your equation and go from there
The general form of the equation of a circle with center at the point ( (a, b) ) and a radius of length ( m ) is given by the equation ( (x - a)^2 + (y - b)^2 = m^2 ). Here, ( (x, y) ) represents any point on the circle. This equation expresses that the distance from any point on the circle to the center ( (a, b) ) is equal to the radius ( m ).
The equation of a circle centered at the origin (0, 0) with a radius of 15 is given by the formula ( x^2 + y^2 = r^2 ), where ( r ) is the radius. Substituting the radius, the equation becomes ( x^2 + y^2 = 15^2 ). Therefore, the equation simplifies to ( x^2 + y^2 = 225 ).
The equation of a circle centered at the origin (0, 0) with a radius of 2 is given by the formula (x^2 + y^2 = r^2), where (r) is the radius. Substituting the radius into the equation, we get (x^2 + y^2 = 2^2), which simplifies to (x^2 + y^2 = 4).
The equation of the circle is given as ((x + 4)^2 + (y - 7)^2 = 132). In the standard form of a circle ((x - h)^2 + (y - k)^2 = r^2), the radius (r) can be determined from the right side of the equation. Here, (r^2 = 132), so the radius (r = \sqrt{132} = 2\sqrt{33}). Thus, the length of the radius of the circle is (2\sqrt{33}).