If you mean: a^2 + b^2 = c^2 then it is Pythagoras' theorem or formula for a right angle triangle
It is a*a + b*b + c*c
It is a^2 + b^2, or a*a + b*b.
a square minus b square
This is the formula: (a3)+(b3)=(a+b)(a2-ab+b2)
Not sure about the original formula, but one that works is b = a/(2c + 1)
It is the same as ab+ac
(A+B)2 = (A+B).(A+B) =A2+AB+BA+B2 =A2+2AB+ B2 So the Answer is A + B the whole square is equal to A square plus 2AB plus B square. Avinash.
(a+b)cube = a cube + b cube + 3a square b + 3ab square
If you're solving for b, then you use the quadratic formula to factor out b. In this case, b= -1/4 or -18/12
The Y-Axis intercept, i.e. when X is zero, Y is b.
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
x=(-b+sqrt(b^2-4*a*c))/(2a) and (-b-sqrt(b^2-4*a*c))/(2a) (This is called the quadratic formula)