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The calculation for normality isn't too hard, but you have to have some info before you can find it.
You need
1 the number of equivalents.
# mol * (subscript on first element of first compound/ number of that element are in the balanced equation) = # equivalents
I am probably confusing you on finding equivalents, but there is not much else I can do. sorry
Using 0.2489 g. of H2C2O4*2H20
is .00197mol so...
.00197 * (2/1) = 3.94*10^-3 equvialents
2 The volume in liters
# mL/1000 = #L
say 43 ml / 1000 +.043 L
so normality would be
(3.94*10^-3)/ .043 = 9.16*10^-2 as normality.
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∙ 13y ago
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