5/9
I just programmed a small software and find a 75,6% of two cards beein next to each other in 15 million random generated decks.
1 in 5 is a square so there are 3 squares and 12 non-squares. If the square is not replaced, and the next card is drawn at random the probability of a non-square is 12/14.
The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.
The probability of five cards being four cards from one suit and one card from another suit is the same as the probability of drawing four cards from one suit multiplied by the probability of drawing one card from another suit, multiplied by 5 (for each of the possible positions this other card can be drawn in). The probability of drawing four cards from one suit is 12/51 x 11/50 x 10/49. The probability of drawing a fifth card from another suit is 39/48. All these numbers multiplied together (and multiplied by 5) come to 0.0429. So the probability of drawing a hand of five cards with four cards from one suit and one card from another is 5.29%
The answer depends on whether the question is in the context of a deck of playing cards or some other collection, whether or not the cards are replaced after picking, whether the cards are selected at random. Since there is no information on any of these aspects, it is not possible to give a useful answer to the question.
depends on how many cards there are. It doesn't make sense because you're asking "what is the probability of a card being drawn at random that is red?" and it doesn't give any clue on what are the other colors or how many cards are in all?
I just programmed a small software and find a 75,6% of two cards beein next to each other in 15 million random generated decks.
number of cards in a deck=52 cards drawn =52 n(s)=52nCr2=1326 number of cards that are queen=4 number of cards that are king=4 n(A)=4nCr1*4nCr1 =4*4 P(A)=n(A)/n(s)=16/1326=6/663
If the pick is completely random, the deck is a standard deck and there are no jokers or any other cards other than the standard 52, the probability is 1/4
4/52 * 4/51 or about .006 This is assuming no other cards were drawn beforehand.
1 in 5 is a square so there are 3 squares and 12 non-squares. If the square is not replaced, and the next card is drawn at random the probability of a non-square is 12/14.
The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.
The probability of drawing a heart from a fair deck is 1 in 4. If the card is replaced then the probability is again 1 in 4. The probability of drawing a card other than a heart is 3 in 4. Once again if the card is replaced then the probability remains 3 in 4
The probability of five cards being four cards from one suit and one card from another suit is the same as the probability of drawing four cards from one suit multiplied by the probability of drawing one card from another suit, multiplied by 5 (for each of the possible positions this other card can be drawn in). The probability of drawing four cards from one suit is 12/51 x 11/50 x 10/49. The probability of drawing a fifth card from another suit is 39/48. All these numbers multiplied together (and multiplied by 5) come to 0.0429. So the probability of drawing a hand of five cards with four cards from one suit and one card from another is 5.29%
The answer depends on whether the question is in the context of a deck of playing cards or some other collection, whether or not the cards are replaced after picking, whether the cards are selected at random. Since there is no information on any of these aspects, it is not possible to give a useful answer to the question.
An independent probability is a probability that is not based on any other event.An example of an independent probability is a coin toss. Each toss is independent, i.e. not related to, any prior coin toss.An example of a dependent probability is the probability of drawing a second Ace from a deck of cards. The probability of the second Ace is dependent on whether or not a first Ace was drawn or not. (You can generalize this to any two cards because the sample space for the first card is 52, while the sample space for the second card is 51.)
Select 2 cards, do not put the 1st back in the deck. This is dependent probability. The outcome of drawing the 2nd card depends on the 1st card drawn. Select a card, look at it and put it back in the deck. Select a 2nd card. These are independent of each other. One does not change the probability for selecting the 2nd.