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From some point A a car traveling at 50mph starts toward some point B 500 miles away 2 hours later a second car at point B starts traveling at 30mph towards A when will the cars meet?
Wiki User
∙ 14y ago
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If car A starts travelling 50mph towards another car B 500 miles away, and the second car starts two hours later towards the first car at 30mph, and can find the meeting time with a system of simultaneous equations in two unknowns.
Start by writing down what you know.
If car A travels at 50, then its distance as a function of time is 50T, so XA = 50T.
If car B travels at 30, but starting two hours later, its distance as a function of time is 30(T-2), so XB = 30(T-2) = 30T - 60.
The two cars travel 500 miles and meet, so XA + XB = 500.
Plug the values of XA and XB into XA + XB = 500.
This gives 50T + 30T - 60 = 500.
Solve for T.
The answer is 7. The cars meet after seven hours.
Cross check:
In seven hours, car A goes 7 times 50, or 350 miles.
In five hours, car B goes 5 times 30, or 150 miles.
150 + 350 is 500.
Wiki User
∙ 14y ago
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