Assuming it's required that all the numbers must be used once and only once: (2 + 8 - 9) x 4! = 4! = 24 Factorials are always handy! I imagine other solutions will follow.
4 x (1+5) = 24
A) 24 * (9-8)
It's done by: (7+4+1) times 2 = 24
Yes I can: (9 - 2 - 4) x 8 = 24
One way: (3 - 2) x 4 x 6 = 24
5! / 4 - 2 * 3
(2 x 6) + 8 + 4
√9 x 2 x (8 - 4) = 3 x 2 x 4 = 24
One way is: (6*4)-3+2+1 = 24
24
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
4*3*2 = 24 of them.