If there were 4 times as many girls as boys, we can represent the number of boys as x and the number of girls as 4x. The total number of children is 200, so we can write the equation x + 4x = 200. Combining like terms, we get 5x = 200. Solving for x, we find x = 40. Therefore, there were 4 * 40 = 160 girls at the concert.
First add 8 and 9 to get 17. Then divide 340 by 17 to get 20. Then times 20 by 8 to find the number of girls or times 20 by 9 to get the number of boys. Number of girls: 160 Number of boys: 180
No. of boys is 8oooand no. of girls is 5000
there are 12 boys in the class
Well, according to your data if 100 people voted, #of girls= 75 and # of boys= 25.
There are 6 girls and 24 boys. Algebraic solution: Let G = number of girls, B= number of boys G+B = 30 B = 4G Substitute to form G + 4G = 30 5G = 30 G = 6 B = 4G = 4 x 6 = 24
This is a problem that has two unknowns (even though you were only asked for one); the number of girls and the number of boys. So you let ,say X, be the number of girls and, say Y, be the number of boys. Since you have two unknowns you try and find two equations from the information given (if you have two unknowns you will need two equations). One equation is the total number of girls & boys is 45. So write; X + Y = 45. The other equation is a bit harder. The girls paid $3 ,so the total money from all the girls is 3X. The boys each paid $5 so the total money from all the boys is 5Y. Now you are told the total money collected is $175 so that must be the money collected from all the boys plus all the girls and you have your second equation; 3X + 5Y = 175. Now you solve these two equations "simultaneously" for X and Y. There are different ways to do this but the easiest one to explain is ; solve for Y in the first equation, as Y = 45 - X , and substitute in the second equation, as; 3X + 5(45 - X) = 175 3X + 225 -5X =175 -2X = -50 X = 25 This is the number of girls. You can now put this answer back into either of the two equations to get Y, the number of boys.
2 boys for every 3 girls 8 boys / 2 boys = 4 times the original ratio 4 times original ratio x 3 girls = 12 girls
There are 12 boys.
The most time boys want girls is in bed
The ratio of girls to boys in this scenario is 5:1. This is determined by dividing the number of girls by the number of boys, which gives us 15 girls divided by 3 boys, resulting in a ratio of 5 girls to 1 boy.
Divide the number of girls by the total number of children (boys + girls).