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200 children were in a concert There were 4 times as many girls than boys How many girls were there?
If there were 4 times as many girls as boys, we can represent the number of boys as x and the number of girls as 4x. The total number of children is 200, so we can write the equation x + 4x = 200. Combining like terms, we get 5x = 200. Solving for x, we find x = 40. Therefore, there were 4 * 40 = 160 girls at the concert.
How do you find how many boys there are in a school of 340 students if you know the ratio is 8 to 9 girls to boys?
First add 8 and 9 to get 17. Then divide 340 by 17 to get 20. Then times 20 by 8 to find the number of girls or times 20 by 9 to get the number of boys. Number of girls: 160 Number of boys: 180
In a group of 80 children there are three times as many boys as girls. How many girls are there?
Let the number of girls be ( x ). Since there are three times as many boys as girls, the number of boys is ( 3x ). Together, the total number of children is ( x + 3x = 4x ). Setting this equal to 80 gives us ( 4x = 80 ), so ( x = 20 ). Therefore, there are 20 girls in the group.
The number of boys and girls are 13000 there ratio is 8 and 5 find the number of boys and girls?
No. of boys is 8oooand no. of girls is 5000
There are boys and girls in a class If the number of girls is multiplied by two and added to the number of boys in the class the sum is 30 If the number of girls is multiplied by two and the number?
there are 12 boys in the class
The number of girls who voted for Fiesta Fun is three times as great as the number of boys who voted for it how many boys voted for Fiesta Fun The number of total votes were 100?
Well, according to your data if 100 people voted, #of girls= 75 and # of boys= 25.
At summer camp the ratio of boys to girls was 101. If there were 30 boys how many girls were there?
If the ratio of boys to girls at summer camp is 10:1, and there are 30 boys, you can set up the ratio equation: ( \frac{30}{g} = 10 ), where ( g ) is the number of girls. Solving for ( g ) gives ( g = \frac{30}{10} = 3 ). Therefore, there were 3 girls at the camp.
If in a group of 30 children there are four times as many boys as girls How many girls are there?
There are 6 girls and 24 boys. Algebraic solution: Let G = number of girls, B= number of boys G+B = 30 B = 4G Substitute to form G + 4G = 30 5G = 30 G = 6 B = 4G = 4 x 6 = 24
If he charged boys 5 dollars and girls 3 dollar the 45 people who came paid a total of 175 dollars How many girls came?
This is a problem that has two unknowns (even though you were only asked for one); the number of girls and the number of boys. So you let ,say X, be the number of girls and, say Y, be the number of boys. Since you have two unknowns you try and find two equations from the information given (if you have two unknowns you will need two equations). One equation is the total number of girls & boys is 45. So write; X + Y = 45. The other equation is a bit harder. The girls paid $3 ,so the total money from all the girls is 3X. The boys each paid $5 so the total money from all the boys is 5Y. Now you are told the total money collected is $175 so that must be the money collected from all the boys plus all the girls and you have your second equation; 3X + 5Y = 175. Now you solve these two equations "simultaneously" for X and Y. There are different ways to do this but the easiest one to explain is ; solve for Y in the first equation, as Y = 45 - X , and substitute in the second equation, as; 3X + 5(45 - X) = 175 3X + 225 -5X =175 -2X = -50 X = 25 This is the number of girls. You can now put this answer back into either of the two equations to get Y, the number of boys.
The ratio of boys to girls in home room is 2:3. If there are 8 boys, how many girls are there?
2 boys for every 3 girls 8 boys / 2 boys = 4 times the original ratio 4 times original ratio x 3 girls = 12 girls
The ratio of the number of girls to the number of boys in a class is 3 to 2. there are 18 girls in class .?
There are 12 boys.
When is the most times boys want girls?
The most time boys want girls is in bed
