No, just one.
i got the answer it is 333
This is a prime number, so its only factors are 1 and 107. Therefore, it only has 2 factors.
The prime factors of 221 are 13 and 17. They're the only prime numbers that will divide evenly into 221 with no remainder.
Prime factorization tells you what prime numbers multiply to get the number. You can see which numbers that number is divisible by to get the multiples and factors.
17 is a prime number because it has only 2 factors which are itself and one
148 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 6 factors of 148 are 1, 2, 4, 37, 74, and 148.The factor pairs of 148 are 1 x 148, 2 x 74, and 4 x 37.The proper factors of 148 are 1, 2, 4, 37, and 74 or,if the definition you are using excludes 1, they are 2, 4, 37, and 74.The prime factors of 148 are 2, 2, and 37. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors of 148 are 2 and 37.The prime factorization of 148 is 2 x 2 x 37 or, in exponential form, 2^2 x 37.
The prime factors of 2x2x3x3x3x5x5x5x5x5 are 2, 3, and 5. This can be determined by breaking down the number into its prime factors, which are the numbers that are divisible only by 1 and themselves. In this case, 2 is a prime factor because it is divisible only by 1 and 2, 3 is a prime factor because it is divisible only by 1 and 3, and 5 is a prime factor because it is divisible only by 1 and 5.
The factors of 81 are numbers that can be multiplied together to give 81. The factors of 81 are 1, 3, 9, 27, and 81. Prime factors are the factors that are prime numbers. The prime factors of 81 are 3 and 3, or written as 3^4.
28 If numbers are relatively prime (no common factor other than 1), just multiply them to get the L.C.M. If the are not relatively prime, then decompose them into prime factors, and find the number got by multiplying those exponents.
5 is a prime factor of 105,20 and 30
1, 2, 4 Method(s) used: # The method is to find all of the factors of each, and then select the numbers that appear in each list. # Another method to find the common factors of numbers is to find the prime factorizations of each one, select all matching prime factors, and then combine them.
Tug McGraw