4,80 moles of Fe contain 28,9062761136.10e23 atoms.
10 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 1023/1 mole Fe) = 1.1 X 1020 atoms of iron ===================
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Fe3O4 has a total of 7 atoms, with 3 iron atoms (Fe) and 4 oxygen atoms (O).
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It depends on the mass of iron. 1 mole Fe = 55.845g = 6.022 x 1023 atoms Fe
To determine the number of atoms present in 400g of iron, we need to first calculate the number of moles of iron using its molar mass (55.85 g/mol). Next, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the total number of atoms in 400g of iron.
There are 10 atoms in Fe2O4 - 2 iron (Fe) atoms and 8 oxygen (O) atoms.
There are 4 atoms in Fe2O2: 2 atoms of iron (Fe) and 2 atoms of oxygen (O).
The density of iron, Fe, at room temperature is 7.874 g/cm3. So 1cm3 of iron has a mass of 7.874g. 1 mole iron = 55.845g Fe = 6.022 x 1023 atoms Fe. 7.874g Fe x 6.022 x 1023 atoms Fe/55.845g Fe = 8.491 x 1022 atoms Fe
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
To find the number of atoms in 4.80 moles of Fe, you need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, 4.80 moles of Fe would contain: 4.80 moles x 6.022 x 10^23 atoms/mol = 2.89 x 10^24 atoms of Fe.